Functions & Formulas

Master the art of manipulating and translating functions to conquer the ACT Math section!

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Function Fundamentals

What is a Function?

A function is a relation that assigns exactly one output to each input. Think of a function as a machine that takes an input, performs an operation, and produces an output.

\[ f(x) = \text{output when the input is } x \]

Key ACT Concept: Function Notation

The ACT frequently tests your understanding of function notation. Remember:

  • If \(f(x) = 2x + 3\), then \(f(5) = 2(5) + 3 = 13\)
  • If \(g(x) = x^2 - 4\), then \(g(-2) = (-2)^2 - 4 = 4 - 4 = 0\)

Example:

If \(f(x) = 3x^2 - 2x + 5\), find \(f(2)\).

Step 1: Substitute \(x = 2\) into the function.

\[ f(2) = 3(2)^2 - 2(2) + 5 \] \[ f(2) = 3(4) - 4 + 5 \] \[ f(2) = 12 - 4 + 5 \] \[ f(2) = 13 \]

Domain and Range

The domain of a function is the set of all possible input values. The range is the set of all possible output values.

Key ACT Concept: Finding Domain Restrictions

Common domain restrictions occur when:

  • The denominator of a fraction equals zero
  • The expression under a square root is negative

Example:

Find the domain of \(f(x) = \frac{x+3}{x-2}\).

Step 1: Identify when the denominator equals zero.

\[ x - 2 = 0 \] \[ x = 2 \]

Step 2: Express the domain.

The domain is all real numbers except \(x = 2\), which we can write as \(\{x | x \neq 2\}\) or \((-\infty, 2) \cup (2, \infty)\).

Linear Functions

Linear functions have the form \(f(x) = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

Key ACT Concept: Interpreting Slope

The slope \(m\) represents the rate of change of the function:

  • Positive slope: Function increases as \(x\) increases
  • Negative slope: Function decreases as \(x\) increases
  • Zero slope: Function is constant

Example:

A car rental company charges $40 per day plus $0.25 per mile. Write a function that gives the cost \(C(m)\) of renting a car for one day and driving \(m\) miles.

Step 1: Identify the fixed cost and the variable cost.

Fixed cost = $40

Variable cost = $0.25 per mile

Step 2: Write the function.

\[ C(m) = 40 + 0.25m \]

Step 3: Interpret the function.

The function \(C(m) = 40 + 0.25m\) gives the cost in dollars for renting a car for one day and driving \(m\) miles. The slope of 0.25 means the cost increases by $0.25 for each additional mile driven.

Quadratic Functions

Quadratic functions have the form \(f(x) = ax^2 + bx + c\), where \(a \neq 0\). The graph of a quadratic function is a parabola.

Key ACT Concept: Vertex Form

The vertex form of a quadratic function is \(f(x) = a(x - h)^2 + k\), where \((h, k)\) is the vertex of the parabola.

  • If \(a > 0\), the parabola opens upward and has a minimum value of \(k\) at \(x = h\)
  • If \(a < 0\), the parabola opens downward and has a maximum value of \(k\) at \(x = h\)

Example:

Find the vertex of the quadratic function \(f(x) = 2x^2 - 12x + 19\).

Step 1: Convert to vertex form by completing the square.

\[ f(x) = 2x^2 - 12x + 19 \] \[ f(x) = 2(x^2 - 6x) + 19 \] \[ f(x) = 2(x^2 - 6x + 9 - 9) + 19 \] \[ f(x) = 2(x - 3)^2 - 18 + 19 \] \[ f(x) = 2(x - 3)^2 + 1 \]

Step 2: Identify the vertex.

The vertex form is \(f(x) = 2(x - 3)^2 + 1\), so the vertex is at \((3, 1)\).

Function Transformations

Function transformations allow us to shift, stretch, compress, or reflect the graph of a function.

Key ACT Concept: Common Transformations

Given a function \(f(x)\):

  • \(f(x) + k\): Shifts the graph up \(k\) units
  • \(f(x) - k\): Shifts the graph down \(k\) units
  • \(f(x - h)\): Shifts the graph right \(h\) units
  • \(f(x + h)\): Shifts the graph left \(h\) units
  • \(a \cdot f(x)\): Vertically stretches (if \(a > 1\)) or compresses (if \(0 < a < 1\)) the graph
  • \(-f(x)\): Reflects the graph across the x-axis
  • \(f(-x)\): Reflects the graph across the y-axis

Example:

Describe the transformation from \(f(x) = x^2\) to \(g(x) = -2(x - 3)^2 + 4\).

Step 1: Identify each transformation.

  • \(-2\): Vertically stretch by a factor of 2 and reflect across the x-axis
  • \((x - 3)\): Shift right 3 units
  • \(+ 4\): Shift up 4 units

Step 2: Describe the complete transformation.

The function \(g(x)\) is obtained from \(f(x) = x^2\) by:

  1. Stretching vertically by a factor of 2
  2. Reflecting across the x-axis
  3. Shifting right 3 units
  4. Shifting up 4 units

The result is a downward-facing parabola with vertex at \((3, 4)\).

Function Operations

Functions can be combined using arithmetic operations (addition, subtraction, multiplication, division) and composition.

Key ACT Concept: Function Composition

The composition of functions \(f\) and \(g\) is denoted as \((f \circ g)(x) = f(g(x))\).

To find \(f(g(x))\), substitute \(g(x)\) for the input variable in \(f\).

Example:

If \(f(x) = 2x + 3\) and \(g(x) = x^2 - 1\), find \((f \circ g)(2)\).

Step 1: Find \(g(2)\).

\[ g(2) = 2^2 - 1 = 4 - 1 = 3 \]

Step 2: Substitute \(g(2)\) into \(f\).

\[ (f \circ g)(2) = f(g(2)) = f(3) = 2(3) + 3 = 6 + 3 = 9 \]

Exponential and Logarithmic Functions

Exponential functions have the form \(f(x) = a \cdot b^x\), where \(a\) and \(b\) are constants and \(b > 0, b \neq 1\).

Logarithmic functions have the form \(f(x) = \log_b(x)\), where \(b\) is the base and \(b > 0, b \neq 1\).

Key ACT Concept: Properties of Logarithms

  • \(\log_b(xy) = \log_b(x) + \log_b(y)\)
  • \(\log_b\left(\frac{x}{y}\right) = \log_b(x) - \log_b(y)\)
  • \(\log_b(x^n) = n \cdot \log_b(x)\)
  • \(b^{\log_b(x)} = x\) for \(x > 0\)
  • \(\log_b(b^x) = x\)

Example:

Solve the equation \(2^{x+1} = 16\).

Step 1: Rewrite 16 as a power of 2.

\[ 16 = 2^4 \]

Step 2: Set the exponents equal.

\[ 2^{x+1} = 2^4 \] \[ x + 1 = 4 \] \[ x = 3 \]

Ready to Practice?

Now that you've learned the fundamentals of functions, test your knowledge with practice problems!

Practice Problems

Test your understanding with these practice problems. Select a difficulty level to begin.

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Functions Challenge

Put your function skills to the test with these timed challenges. Complete them to earn badges and level up your character!

Function Notation Challenge

100 XP

Evaluate 5 function expressions in 5 minutes.

5 minutes
5 problems

Function Transformations Challenge

150 XP

Identify 5 function transformations in 7 minutes.

7 minutes
5 problems

Function Operations Challenge

200 XP

Solve 5 function composition problems in 10 minutes.

10 minutes
5 problems

Functions ACT Test Simulation

Take a timed test that simulates the function questions you'll see on the ACT. This will help you identify your strengths and areas for improvement.

Test Details

  • Time Limit: 15 minutes
  • Questions: 10 function questions in ACT format
  • Topics Covered: Function notation, domain and range, transformations, and operations
  • Scoring: Instant results with detailed explanations

Ready to Test Your Skills?

This simulation will help you prepare for the actual ACT math section.